• # question_answer At rest, a liquid stands at the same level in the tubes. As the system is given an acceleration a towards the right. A height difference h occurs as shown in the figure. The value of h is A)  $\frac{aL}{2g}$                                              B)  $\frac{gL}{2a}$ C)  $\frac{gL}{a}$                                 D)  $\frac{aL}{g}$

Newton's equations are  A$\Delta p\sin \theta =ma$...(i) and A$\Delta p\cos \theta =mg$...(ii) By Eqs. (i) and (ii), we get $\tan \theta =\frac{a}{g}=\frac{h}{L}$ or$h=\frac{aL}{g}$