• # question_answer x g of non-electrolyte compound of molecular mass 200, when dissolved in 1L of 0.05 M NaCl solution, the osmotic pressure of the resulting solution is found to be 4.92 atm at $27{}^\circ C$. Assuming the complete dissociation of NaCI and ideal behaviour of solution, the value of x would be A)  10 g                       B)  20.0g                  C)  40.0 g                   D)  80.0 g

While solving this process, students are advised to use the concept of osmotic pressure as follows $\therefore$$\pi =C\,RT=\left\{ \frac{x}{200}+2\times 0.05 \right\}0.0821\times 300$ $\Rightarrow$$\frac{x}{200}+0.1=\frac{4.92}{0.0821\times 300}$ $\therefore$$\frac{x}{200}+0.1=0.2\Rightarrow x=0.1\times 200=20g$