A) 5.0
B) 3.0
C) 1.0
D) 5.5
Correct Answer: C
Solution :
Moles of pure\[CuS{{O}_{4}}=0.24=\]moles of \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]reacted with\[{{l}_{2}}\]. Moles of\[N{{a}_{2}}{{S}_{2}}{{O}_{3}}=240\times {{10}^{-3}}\times M\]\[=0.24\] So, \[M=1.0\]You need to login to perform this action.
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