A) \[{{v}_{1}}=\frac{{{v}_{2}}}{\sin \theta }\]
B) \[{{v}_{1}}={{v}_{2}}\]
C) \[{{v}_{2}}=\frac{{{v}_{1}}}{\sin \theta }\]
D) \[d{{v}_{1}}={{v}_{2}}\cos \theta \]
Correct Answer: C
Solution :
\[\sin \theta =\frac{AC}{AB}\] \[\sin \theta =\frac{dY}{dX}\] Differentiate above expression for constant\[\theta \] \[\sin \theta =\frac{{{v}_{1}}}{{{v}_{2}}}\] \[{{v}_{2}}=\frac{{{v}_{1}}}{\sin \theta }\]You need to login to perform this action.
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