A) 10 g
B) 20.0g
C) 40.0 g
D) 80.0 g
Correct Answer: B
Solution :
While solving this process, students are advised to use the concept of osmotic pressure as follows \[\therefore \]\[\pi =C\,RT=\left\{ \frac{x}{200}+2\times 0.05 \right\}0.0821\times 300\] \[\Rightarrow \]\[\frac{x}{200}+0.1=\frac{4.92}{0.0821\times 300}\] \[\therefore \]\[\frac{x}{200}+0.1=0.2\Rightarrow x=0.1\times 200=20g\]You need to login to perform this action.
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