A) \[\frac{1}{101}\Omega \]
B) \[\frac{1}{100}\Omega \]
C) \[\frac{1}{99}\Omega \]
D) \[\frac{1}{9}\Omega \]
Correct Answer: C
Solution :
Idea An ammeter have low resistance in parallel and its value is given by \[S=\frac{{{i}_{g}}r}{i-{{i}_{g}}}\]
Given, \[{{i}_{g}}=10mA=0.01A,r=1\Omega ,i=1A\] As, \[{{V}_{A}}-{{V}_{B}}={{i}_{g}}r=(l-{{i}_{g}})S\] 
\[\Rightarrow \]\[S=\frac{{{i}_{g}}r}{(l-{{i}_{g}})}=\frac{0.01\times 1}{1-0.01}=\frac{1}{99}\Omega \] (shunt is small resistance in parallel) TEST Edge Galvanometer can be converted into voltmeter as well, for this a high resistance is connected in series with the galvanometer. 
\[R=\frac{V}{{{I}_{g}}}-{{R}_{g}}\]
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