A) \[{{10}^{4}}J/K\]
B) \[1.31\times {{10}^{3}}J/K\]
C) \[1.68\times {{10}^{4}}J/K\]
D) \[1.68\times {{10}^{3}}J/K\]
Correct Answer: B
Solution :
\[\Delta S=\int_{{}}^{{}}{\frac{dQ}{T}}=\int_{{{T}_{1}}}^{{{T}_{2}}}{\frac{msdT}{T}}=ms\ln \left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)\] \[=1\times 4190\,\,\ln \,\left( \frac{373}{273} \right)\,\] \[=1.31\times {{10}^{3}}\,\,J/K\]
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