A) The body which has been thrown horizontally
B) The body which has been dropped
C) Both are reaching the ground simultaneously
D) Depends on the velocity with which the 1st body has been projected horizontally
Correct Answer: C
Solution :
Since vertical displacement is same, as well as initial velocity in vertical downward direction is zero for both the bodies, So, \[h=\frac{gt_{1}^{2}}{2}\](for horizon throwing) \[h=\frac{gt_{2}^{2}}{2}\] (for dropping) \[\therefore \] \[{{t}_{1}}={{t}_{2}}\]You need to login to perform this action.
You will be redirected in
3 sec