A) \[\frac{2{{E}_{1}}}{{{N}_{0}}},\frac{2({{E}_{1}}-{{E}_{2}})}{{{N}_{0}}}\]
B) \[\frac{2{{E}_{1}}}{{{N}_{0}}},\frac{2{{E}_{2}}}{{{N}_{0}}}\]
C) \[\frac{({{E}_{1}}-{{E}_{2}})}{{{N}_{0}}},\frac{2{{E}_{2}}}{{{N}_{0}}}\]
D) None is correct
Correct Answer: B
Solution :
\[X(g)\xrightarrow[{}]{{}}{{X}^{+}}(g)+{{e}^{-}}\] If I is ionisation energy, then \[\therefore \] \[\frac{{{N}_{0}}}{2}(I)={{E}_{1}}\] \[\therefore \] \[I=\frac{2{{E}_{1}}}{{{N}_{0}}}\] If E is electron affinity, then \[X(g)+{{e}^{-}}\xrightarrow[{}]{{}}{{X}^{-}}(g)\] \[\frac{{{N}_{0}}}{2}(E)={{E}_{2}}\] \[\therefore \]\[E=\frac{2{{E}_{2}}}{{{N}_{0}}}\]You need to login to perform this action.
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