A) He > Ne > Ar > Kr > Xe
B) Xe > Kr > Ar > Ne > He
C) Kr > Xe > He > Ar = Ne
D) Ar > Kr > Xe > He > Ne
Correct Answer: B
Solution :
He has the weakest van der Waals' forces of attraction due to its smallest size and hence, has lowest boiling point. In other words, its liquefaction is difficult. As the size of the noble gas increases from He to Xe, van der Waals' forces increases and consequently boiling point increases and liquefaction becomes easy.
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