A) \[\frac{{{k}_{1}}}{{{k}_{2}}}\]
B) \[\sqrt{\frac{{{k}_{1}}}{{{k}_{2}}}}\]
C) \[\frac{{{k}_{2}}}{{{k}_{1}}}\]
D) \[\sqrt{\frac{{{k}_{2}}}{{{k}_{1}}}}\]
Correct Answer: D
Solution :
Since maximum velocity is same, so maximum KE ie, TE would be same. Also maximum PE would also be same. Let \[{{A}_{1}}\] and \[{{A}_{2}}\] be the amplitudes of two bodies A and B respectively, \[\frac{{{k}_{1}}A_{1}^{2}}{2}=\frac{{{k}_{2}}A_{2}^{2}}{2}\] \[\frac{A_{1}^{{}}}{{{A}_{2}}}=\sqrt{\frac{{{k}_{2}}}{{{k}_{1}}}}\]You need to login to perform this action.
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