A) A = retention product, B = optically inactive,
B) A and B both are same optically active retention product
C) A and B both are optically inactive
D) A is optically inactive and B is retention product
Correct Answer: A
Solution :
\[{{C}_{6}}{{H}_{5}}-CH=CH-\overset{+}{\mathop{C}}\,H-C{{H}_{3}}\xrightarrow[{}]{{}}\] \[{{C}_{6}}{{H}_{5}}CH=CH\underset{(\pm )}{\mathop{\underset{\text{racemic}\,\text{mixture}}{\mathop{-\underset{\begin{smallmatrix} \text{ }\!\!|\!\!\text{ } \\ \text{OH} \end{smallmatrix}}{\mathop{\text{CH}}}\,-C{{H}_{3}}}}\,}}\,\] (-OH gets added from both sides)You need to login to perform this action.
You will be redirected in
3 sec