A) \[e=\frac{{{\ell }_{1}}-3{{\ell }_{2}}}{2}\]
B) \[e=\frac{{{\ell }_{2}}-3{{\ell }_{1}}}{2}\]
C) \[e=\frac{{{\ell }_{1}}-{{\ell }_{2}}}{2}\]
D) \[e=\frac{{{\ell }_{2}}-{{\ell }_{1}}}{2v}\]
Correct Answer: B
Solution :
With end correction, \[{{\ell }_{1}}+e=\frac{\lambda }{4}\] and \[{{\ell }_{2}}+e=\frac{3\lambda }{4}\] \[\therefore \] \[{{\ell }_{2}}+e=3\times ({{\ell }_{1}}+e)\] \[\Rightarrow \,\,2e={{\ell }_{2}}-3{{\ell }_{1}}\] \[\therefore \] End correction \[=e=\frac{{{\ell }_{2}}-3{{\ell }_{1}}}{2}\]
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