2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-7

  • question_answer
    A body of mass 6 kg moves in a straight line according to the equation \[x=({{t}^{3}}-8t)m\] where t is in second. The momentum of the body at the end of 4th second is (in kg m/s)

    A)  560                       

    B)  192

    C)  240                       

    D)  6

    Correct Answer: C

    Solution :

    \[x={{t}^{3}}-8t\] Differentiating we get \[\upsilon =3{{t}^{2}}-8\] \[\upsilon {{|}_{t=4}}=3\times {{4}^{2}}-8=40\,m/s\] Momentum \[=mv=6\times 40=240\,kg\,m/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner