A) \[\frac{P}{\sqrt{2\pi }}\]
B) \[\sqrt{2P}\]
C) \[\frac{P}{2\pi }\]
D) \[\frac{\sqrt{2}P}{\pi }\]
Correct Answer: C
Solution :
Pitch \[=\upsilon \,\cos \theta \times \frac{2\pi r}{\upsilon }=2\pi r\,\cos \theta =2\pi r=\frac{1}{\sqrt{2}}\] \[\therefore \] Radius of circle \[r=\frac{P\sqrt{2}}{2\pi }=\frac{P}{\sqrt{2}\pi }\] Radius of helix \[=r\cos {{45}^{o}}=\frac{P}{2\pi }\]You need to login to perform this action.
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