A) \[\frac{{{r}^{2}}{{t}^{2}}}{R}\]
B) \[\frac{{{(R+r)}^{2}}{{t}^{2}}}{r}\]
C) \[(R+r){{t}^{2}}\]
D) Depends on mass
Correct Answer: C
Solution :
Torque \[=\vec{r}\times \vec{F}=(R+r)\times 2t\] Since \[L=\int_{{}}^{{}}{\tau dt}\] we get \[L=\int_{{}}^{{}}{2(R+r)tdt=2(R+r)\frac{{{t}^{2}}}{2}=(R+r){{t}^{2}}}\]
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