A) \[CaS{{O}_{4}}\]
B) \[BeS{{O}_{4}}\]
C) \[BaS{{O}_{4}}\]
D) \[SrS{{O}_{4}}\]
Correct Answer: B
Solution :
Due to smaller size of \[B{{e}^{2+}}\] ion and high charge density it has more hydration enthalpy.
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