A) \[{{H}_{2}}S\] is oxidized to \[SO_{4}^{2-}\]
B) \[{{H}_{2}}S\] is oxidized to S
C) \[SO_{3}^{2-}\]gets oxidized to \[SO_{4}^{2-}\]
D) \[S{{n}^{2+}}\] gets oxidized to \[S{{n}^{4+}}\]
Correct Answer: A
Solution :
\[2KMn{{O}_{4}}+5{{H}_{2}}S+3{{H}_{2}}S{{O}_{4}}\xrightarrow{\,}\]\[{{K}_{2}}S{{O}_{4}}+2MnS{{O}_{4}}+5S+8{{H}_{2}}O\]
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