A) \[^{120}{{C}_{15}}\]
B) \[^{135}{{C}_{15}}\]
C) \[^{256}{{C}_{15}}\]
D) \[^{255}{{C}_{15}}\]
Correct Answer: B
Solution :
If we put minimum number of balls in each box, then remaining 256 - 136 = 120 identical balls can be put in \[^{120+16-1}{{C}_{16}}-1{{=}^{135}}{{C}_{15}}\] ways without restriction.You need to login to perform this action.
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