A) 19
B) 17
C) 15
D) 21
Correct Answer: A
Solution :
The given expression can be written as \[S={{\left( {{\alpha }^{{{\log }_{3}}7}} \right)}^{{{\log }_{3}}7}}+{{\left( {{b}^{{{\log }_{7}}11}} \right)}^{{{\log }_{7}}11}}+{{\left( {{c}^{{{\log }_{11}}25}} \right)}^{{{\log }_{11}}25}}\] \[={{27}^{{{\log }_{3}}7}}+{{49}^{{{\log }_{7}}11}}+{{\left( \sqrt{11} \right)}^{{{\log }_{11}}25}}\] \[={{7}^{3}}+{{11}^{2}}+5\] \[=469\] \[\therefore \] Sum of digits = 19.You need to login to perform this action.
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