A) \[{{E}_{1}}>{{E}_{2}}>{{E}_{3}}\]
B) \[{{E}_{1}}<{{E}_{2}}<{{E}_{3}}\]
C) \[{{E}_{1}}>{{E}_{3}}>{{E}_{2}}\]
D) \[{{E}_{2}}>{{E}_{1}}>{{E}_{3}}\]
Correct Answer: D
Solution :
\[\lambda =\frac{h}{p}=\frac{h}{\sqrt{2mE}}\]\[\Rightarrow \,E=\frac{{{h}^{2}}}{2m{{\lambda }^{2}}}\propto \frac{1}{m}\]You need to login to perform this action.
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