JEE Main & Advanced Sample Paper JEE Main Sample Paper-9

  • question_answer
    . Find the real angle of dipole if a magnet is suspended at an angle of \[30{}^\circ \] to the magnetic meridian & the dip needle makes an angle of \[45{}^\circ \] with horizontal

    A) \[{{\tan }^{-1}}\left( \frac{\sqrt{3}}{2} \right)\]                 

    B) \[{{\tan }^{-1}}\left( \sqrt{3} \right)\]

    C) \[{{\tan }^{-1}}\left( \sqrt{\frac{3}{2}} \right)\]                 

    D) \[{{\tan }^{-1}}\left( \frac{2}{\sqrt{3}} \right)\]

    Correct Answer: A

    Solution :

    Let \[\theta \]is the dipole angle, then from definition of dip angle\[\tan \theta =\frac{V}{H}\]where V & H are vertical & horizontal component of earth's magnetic field respectively. From given information, \[\tan {{45}^{o}}=\frac{V}{H\cos 30}\] \[\Rightarrow \]\[\theta ={{\tan }^{-1}}\left( \frac{\sqrt{3}}{2} \right)\]


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