A) \[\frac{V}{16}\]
B) \[\frac{V}{17}\]
C) \[\frac{16V}{17}\]
D) \[\frac{17V}{16}\]
Correct Answer: B
Solution :
\[V=\frac{\pi {{P}_{1}}{{r}^{4}}}{8\eta \ell }=\frac{{{P}_{2}}}{\frac{8\eta \ell }{\pi {{r}^{4}}}}\] From given information, \[{{P}_{1}}=V'\left( \frac{8\eta \ell }{\pi {{r}^{4}}}+\frac{16(8\eta \ell )}{\pi {{r}^{4}}} \right)=V\left( \frac{8\eta \ell }{\pi {{r}^{4}}} \right)\]\[V'=\frac{V}{17}\]
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