A) 90
B) 200
C) 180
D) 380
Correct Answer: C
Solution :
\[{{M}_{2}}=\frac{{{w}_{2}}{{M}_{1}}\times {{p}^{0}}}{{{w}_{1}}({{p}^{0}}-{{p}_{s}})}\] Where, \[{{M}_{2}}=\]molar mass of solute \[{{w}_{2}}=\]weight of solute \[{{M}_{1}}=\] molar mass of solvent \[{{w}_{1}}=\]weight of solvent \[{{p}^{0}}=\]vapour pressure of pure solvent \[{{p}_{s}}=\]vapour pressure of solution \[=\frac{5\times 18\times 3000}{100\times (3000-2985)}=180\]You need to login to perform this action.
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