A) 0
B) \[\frac{1}{2}\]
C) 1
D) 2
Correct Answer: C
Solution :
Let the point \[A=(t,{{t}^{2}});{{m}_{OA}}=t;\]\[{{m}_{AB}}=-\frac{1}{t}\] Equation of \[AB,y-{{t}^{2}}=-\frac{1}{t}(x-{{t}^{2}})\] On putting x = 0, we get \[h={{t}^{2}}+1\](as\[x\to 0\]then \[t\to 0\]) Now,\[\underset{t\to 0}{\mathop{\lim }}\,(h)=\underset{t\to 0}{\mathop{\lim }}\,(1+{{t}^{2}})=1\]You need to login to perform this action.
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