A) \[11.2L{{H}_{2(g)}}\] at STP is produced for every mole of \[HC{{l}_{(ag)}}\] consumed.
B) \[6LHC{{l}_{(aq)}}\]is consumed for every 3L H2(g) produced
C) \[33.6L\,{{H}_{2}}_{(g)}\] is produced regardless of temperature and pressure for every mole of Al that reacts.
D) \[67.2L\,{{H}_{2}}_{(g)}\] at STP is produced for every mole of Al that reacts.
Correct Answer: A
Solution :
\[2A{{l}_{(s)}}+6HC{{l}_{(aq)}}\to 2A{{l}^{3+}}_{(aq)}+6C{{l}^{-}}_{(aq)}+3{{H}_{2(g)}}\] At STP 6 moles of HCI produces 3 moles of \[{{H}_{2}}\] or \[3x22.4\text{ }L\] of\[{{H}_{2}}\] \[\therefore \]1 mole of HCI produces\[\frac{3\times 22.4}{6}=11.2L\] or \[{{H}_{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
