A) \[\frac{19}{50}\]
B) \[\frac{19}{100}\]
C) \[\frac{31}{50}\]
D) \[\frac{31}{100}\]
Correct Answer: A
Solution :
\[f'(x)={{x}^{2}}+ax+b>0\Rightarrow {{a}^{2}}-4b<0\] \[b=1\Rightarrow a=1\] \[b=2\Rightarrow a=1,2\] \[b=3\Rightarrow a=1,2,3\] \[b=4\Rightarrow a=1,2,3\] \[b=5\Rightarrow a=1,2,3,4\] \[\begin{align} & : \\ & : \\ \end{align}\] \[b=10\Rightarrow a=1,2,3,4,5,6\] \[\therefore \]total pairs = 38 Probability\[=\frac{19}{50}\]You need to login to perform this action.
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