JEE Main & Advanced Sample Paper JEE Main Sample Paper-9

  • question_answer
    \[RN{{H}_{2}}\]reacts with \[{{C}_{6}}{{H}_{5}}S{{O}_{2}}Cl\] in aqueous KOH to give a clear solution. On acidification, a precipitate is obtained which is due to the formation of

    A)  \[R-\underset{\begin{smallmatrix}  | \\  H \end{smallmatrix}}{\overset{\begin{smallmatrix}  H \\  | \end{smallmatrix}}{\mathop{{{N}^{+}}}}}\,-S{{O}_{2}}{{C}_{6}}{{H}_{5}}O{{H}^{-}}\]

    B)  \[R-{{N}^{-}}S{{O}_{2}}{{C}_{6}}{{H}_{5}}{{K}^{+}}\]

    C)  \[{{C}_{6}}{{H}_{5}}S{{O}_{2}}N{{H}_{2}}\]         

    D)  \[R-NH-S{{O}_{2}}-{{C}_{6}}{{H}_{5}}\]

    Correct Answer: B

    Solution :

    \[\underset{\begin{smallmatrix}  Benzene\,sulphonyl \\  chloride \end{smallmatrix}}{\mathop{{{C}_{6}}{{H}_{5}}S{{O}_{2}}Cl}}\,+RN{{H}_{2}}\to \underset{\begin{smallmatrix}  N-alkyl\,benzene \\  sulphonomide \end{smallmatrix}}{\mathop{RNHS{{O}_{2}}{{C}_{6}}{{H}_{5}}}}\,\xrightarrow[{}]{KOH}\]\[\underset{sa\operatorname{lub}le\,in\,KOH}{\mathop{R-NHS{{O}_{2}}{{C}_{6}}{{H}_{5}}}}\,\]


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