A) \[{{x}^{2}}+Ax+2A=0\]
B) \[{{x}^{2}}-2Ax+2A=0\]
C) \[{{x}^{2}}-Ax+2A=0\]
D) none of these
Correct Answer: B
Solution :
Let the equation of the line be \[\frac{x}{a}+\frac{y}{b}=1\] Area of \[\Delta POQ=\frac{1}{2}ab,\]Given \[\frac{1}{2}ab=A\Rightarrow ab=2A\] Since line (1) passes through (1, 1) \[\therefore \]\[\frac{1}{a}+\frac{1}{b}=1\]or\[a+b=ab\Rightarrow a+b=2A\] \[\therefore \]Required quadratic equation is \[{{x}^{2}}-(a+b)x+ab=0\]or\[{{x}^{2}}-2Ax+2A=0\]You need to login to perform this action.
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