A) \[{{F}_{4}}>{{F}_{2}}\]
B) \[{{\overrightarrow{F}}_{3}}=-{{\overrightarrow{F}}_{4}}\]
C) \[{{F}_{2}}>{{F}_{1}}\]
D) \[{{\overrightarrow{F}}_{2}}=-{{\overrightarrow{F}}_{4}}\]
Correct Answer: D
Solution :
FBD of various components of system is shown in figure. Since balloon is moving at constant speed, net force on balloon & student must be zero. On balloon some other force must be acting which is not mentioned. For equilibrium of student \[{{\vec{F}}_{2}}+{{\vec{F}}_{4}}=0\Rightarrow {{\vec{F}}_{2}}=-{{\vec{F}}_{4}}.\] Relation between \[{{F}_{1}},{{F}_{2}}\]can't be known. \[{{\vec{F}}_{1}}\And {{\vec{F}}_{3}}\]are forming an action reaction pair.You need to login to perform this action.
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