A) 4k+1
B) 2k+1
C) 2k-1
D) 4k-3
Correct Answer: A
Solution :
On putting x - 1 = y, we get \[f(y)=2{{(1+y)}^{2}}-3(1+y)+1=2{{y}^{2}}+y\] \[\therefore \]\[f(x)=2{{x}^{2}}+x\] Which is a polynomial hence differentiable \[\therefore \]\[f'(x)=4k+1\]
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