A) \[\left[ Co{{\left( {{H}_{2}}O \right)}_{4}}C{{l}_{2}} \right]Cl.2{{H}_{2}}O\]
B) \[\left[ Co{{\left( {{H}_{2}}O \right)}_{3}}C{{l}_{3}} \right].3{{H}_{2}}O\]
C) \[\left[ Co{{\left( {{H}_{2}}O \right)}_{6}} \right]C{{l}_{3}}\]
D) \[\left[ Co{{\left( {{H}_{2}}O \right)}_{5}}CI \right]C{{l}_{2}}.{{H}_{2}}O\]
Correct Answer: D
Solution :
| Moles of complex \[=\frac{Molarity\times Valume\left( mL \right)}{1000}\]\[=\frac{100\times 0.1}{1000}=0.01\operatorname{mole}\] |
| Moles of ions precipitated with excess of \[{{\operatorname{AgNO}}_{3}}=\frac{1.2\times {{10}^{22}}}{6.02\times {{10}^{23}}}=0.02\operatorname{moles}\] |
| Now, \[0.01\times n=0.02\] |
| \[\therefore n=2\] |
| It means \[2C{{l}^{-}}\]ions is present in ionization sphere \[\therefore Complex\,is\,\left[ Co{{\left( {{H}_{2}}O \right)}_{5}}Cl \right]C{{l}_{2}}.{{H}_{2}}O\] |
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