A) \[\operatorname{HCOOH}\]
B) \[{{(COOH)}_{2}}\]
C) \[{{\operatorname{CH}}_{3}}COOH\]
D) \[{{\operatorname{NH}}_{3}}\]
Correct Answer: B
Solution :
the given set of reactions can be represented |
as below:\[\operatorname{Aq}.NaOH\xrightarrow[High\,\,tem.,]{Gas\,B}Sod.\,salt\,of\,acid\,A\] \[\xrightarrow[(ii){{H}_{2}}S{{O}_{4}}]{(i)NaOH(heat)}Dibasic\,Acid,\,C\] |
Calculation of molecular formula of C |
\[%\operatorname{of}\,H=\frac{2}{18}\times \frac{0.08}{0.40}\times 100=2.22%\]\[%\operatorname{of}\,C=\frac{12}{44}\times \frac{0.39}{0.40}\times 100=27.30%\]\[%\operatorname{of}\,O=100-\left( 2.22+27.30 \right)=71.48%\] |
By usual method, empirical formula of acid C is \[{{\operatorname{CHO}}_{2}}\] |
\[\operatorname{Eq}.wt\,of\,acid\,C=\left( \frac{1.0}{0.71}\times 108 \right)-107=45\] |
Mol. Wt. of acid \[C=45\times 2=90\] |
\[\therefore \]Mol. formula of \[C={{C}_{2}}{{H}_{2}}{{O}_{4}}\] |
Since it is dicarboxylic and it must have two |
\[-COOH\,groups\,hence\,C\,is\,\,\underset{\underset{Oxilic\,acid}{\mathop COOH}\,}{\mathop{\overset{\underset{{}}{\mathop COOH}\,}{\mathop{|}}\,}}\,\,\] |
Complete series of reaction will be,\[2NaOH\left( aq. \right)\xrightarrow{2C{{O}_{2}}\left( B \right)}\underset{\underset{{}}{\mathop HCOONa}\,}{\mathop{\overset{\overset{{}}{\mathop HCOONa}\,}{\mathop{+}}\,}}\,\] |
\[\xrightarrow[heat]{NaOH}\underset{\underset{{}}{\mathop COONa}\,}{\mathop{\overset{\overset{{}}{\mathop COONa}\,}{\mathop{|}}\,}}\,\xrightarrow{{{H}_{2}}S{{O}_{4}}}\underset{\underset{(C)}{\mathop COONa}\,}{\mathop{\overset{\overset{{}}{\mathop COONa}\,}{\mathop{|}}\,}}\,\] |
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