A) {x : x > 0}
B) {x : x < 0}
C) {x : x > 1}
D) {x : x < 1}
Correct Answer: B
Solution :
\[{{f}^{1}}\,(x)=a\,({{e}^{ax}}-{{e}^{-\,ax}})<0\] |
\[\Rightarrow \] \[{{e}^{ax}}>{{e}^{-\,ax}}\] \[(\because a<0)\] |
\[\Rightarrow \] \[x<0\] |
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