A) \[8\times {{10}^{10}}\]
B) \[8\times {{10}^{6}}\]
C) \[7\times {{10}^{10}}\]
D) \[7\times {{10}^{9}}\]
Correct Answer: C
Solution :
As, 11.46 days is three times the half-life of Radon. So, decay scheme is as follows 3.82 days. |
So, only \[1\times {{10}^{10}}\]active nuclii remains after 3-half lives. |
So, \[7\times {{10}^{10}}\]disintegrations would occur in 11.46 days. |
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