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KVPY Sample Paper KVPY Stream-SX Model Paper-10

  • question_answer
    In Duma's method of estimation of nitrogen, 0.35 g of an organic compound gave 55 mL of nitrogen at 300 K temperature and 715 mm pressure. The percentage composition of Nitrogen in the compound would be: (Aqueous Tension at 300 K = 15 mm)

    A) 15.46               

    B) 16.46

    C)  17.46              

    D) 14.46

    Correct Answer: B

    Solution :

    Given Wt. of compound taken (w)\[=0.35g\] volume of nitrogen collected (V) =55mL room temperature (T)=300Ka Atmospheric pressure (P)=715mm
    Aq. Tension \[\left( \rho  \right)\]15=mm
    Calculation ? volume of \[{{\operatorname{N}}_{2}}\]at NTP\[=\frac{\left( P-\rho  \right)\times V}{T}\times \frac{273}{760}mL\]\[=\frac{\left( 715-15 \right)\times 55}{300}\times \frac{273}{760}=46.098mL\]
    \[%\,of\,nitrogen\]\[=\frac{28\times vol.of\,{{N}_{2}}at\,NTP\times 100}{22400\times Wt\,of\,organic\,compound}\]\[=\frac{28\times 46.098\times 100}{22400\times 0.35}=16.46%\]


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