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KVPY Sample Paper KVPY Stream-SX Model Paper-10

  • question_answer
    Among \[N{{H}_{3}}HN{{O}_{3}},Na{{N}_{3}}\,and\,M{{g}_{3}}{{N}_{2}}\] the Number of molecules having nitrogen in negative Oxidation state is

    A) 1                                 

    B) 2

    C) 3                     

    D) 4

    Correct Answer: C

    Solution :

    Calculating the oxidation state of nitrogen in give molecules;
    Oxidation state of N in\[{{\operatorname{NH}}_{3}}\]is \[x+3\times \left( +1 \right)=0\,\operatorname{or}\,x=-3\]
                           
    Oxidation state of N in \[{{\operatorname{NaNO}}_{3}}\]
    \[1+x+3\times \left( -2 \right)=0\operatorname{or}\,x=+5\]
    Oxidation state of N in \[{{\operatorname{NaN}}_{3}}\]\[+1+3x=0\,\operatorname{or}\,x=-\frac{1}{3}\]
                           
    Oxidation state of N in\[{{\operatorname{mg}}_{3}}{{N}_{2}}\] is \[3\times 2+2x=0\,\operatorname{or}x=-3\]
    Thus 3 molecules (i.e.\[{{\operatorname{NH}}_{3}}\], \[{{\operatorname{NaN}}_{3}}\]and\[{{\operatorname{mg}}_{3}}{{N}_{2}}\]) have nitrogen in negative oxidation state.


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