A) Bonding is 100% ionic in both the molecules.
B) AB has more ionic bond character than CD.
C) AB has lesser ionic bond character than CD.
D) Bonding is nearly covalent in both the molecules.
Correct Answer: C
Solution :
| dipole moment =Electric charge\[\times \]Bond length |
| D.M, of AB molecule \[=4.8\times {{10}^{-10}}\times 2.82\times {{10}^{-10}}=13.54D\] |
| D.M. of CD molecule\[D.=4.8\times {{10}^{-10}}\times 2.67\times {{10}^{-10}}=12.81D\] |
| Now % ionic character \[=\frac{Actual\,dipole\,moment\,of\,the\,bond}{Dipole\,moment\,of\,pure\,ionic\,compound}\times 100\] |
| \[=\frac{10.41}{13.53}\times 100=76.94%\] |
| \[%\]ionic character in CD\[=\frac{10.27}{12.81}\times 100=80.17%\] |
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