A) \[f\,(x)\] is a many-one and into function
B) \[f\,(x)=0\]for exactly five number of values of x
C) \[f\,(x)=0\] for only two real values
D) none of these
Correct Answer: A
Solution :
| \[f\,(x)={{[x]}^{2}}+[x+1]-3=\{[x]+2\}\,\,\{[x]-1\}\] |
| So, x = 1, 1.1, 1.2, ? \[\Rightarrow \] \[f\,(x)=0\] |
| \[\therefore \] f(x) is many one |
| only integral values will be attained |
| \[\therefore \] f(x) is into |
You need to login to perform this action.
You will be redirected in
3 sec
