A) 2
B) 1
C) 3
D) 4
Correct Answer: A
Solution :
\[\sin x-\sin 2x+\sin 3x=0\] |
\[\Rightarrow \] \[(\sin x+\sin 3x)-\sin 2x=0\] |
\[\Rightarrow \] \[2\sin x,\cos x-\sin 2x=0\] |
\[\Rightarrow \] \[\sin 2x\,(2\cos x-1)=0\] |
\[\Rightarrow \] \[sin2x=0\] |
or \[\cos x=\frac{1}{2}\] |
\[\Rightarrow \] \[x=0,\frac{\pi }{3}.\] |
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