KVPY Sample Paper KVPY Stream-SX Model Paper-11

  • question_answer
    If \[f(x)=\int{\frac{5{{x}^{8}}+7{{x}^{6}}}{{{({{x}^{2}}+1+2{{x}^{7}})}^{2}}}dx,}\]\[(x\ge 0)\] and \[f(0)=0.\] then the value of\[f(1)\] is:

    A) \[-\frac{1}{2}\]                         

    B) \[\frac{1}{2}\]

    C) \[-\frac{1}{4}\]                         

    D) \[\frac{1}{4}\]

    Correct Answer: D

    Solution :

    \[\int{\frac{5{{x}^{8}}+7{{x}^{6}}}{{{({{x}^{2}}+1+2{{x}^{7}})}^{2}}}dx}=\int{\frac{5{{x}^{-\,6}}+7{{x}^{-\,8}}}{{{\left( \frac{1}{{{x}^{7}}}+\frac{1}{{{x}^{5}}}+2 \right)}^{2}}}dx}\]
    \[=\,\frac{1}{2+\frac{1}{{{x}^{5}}}+\frac{1}{{{x}^{7}}}}+C\]
    As \[f(0)-0,\] \[f(x)=\frac{{{x}^{7}}}{2{{x}^{7}}+{{x}^{2}}+1}\]
                \[f(1)=\frac{1}{4}.\]


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