A) \[cc'+a+a'=0\]
B) \[aa'+c+c'=0\]
C) \[ab'+bc'+1=0\]
D) \[bb'+cc'+1=0\]
Correct Answer: B
Solution :
Line \[x=ay+b\] |
\[z=cy+d\] |
\[\Rightarrow \] \[\frac{x-b}{a}=\frac{y}{1}=\frac{z-d}{c}\] |
Line \[x=a'z+b'\] |
\[y=c'z+d'\] |
\[\Rightarrow \] \[\frac{x-b'}{a'}=\frac{y-d'}{c'}=\frac{z}{1}\] |
Given both the lines are perpendicular \[\Rightarrow \] \[aa'+c'+c=0\] |
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