A) 2
B) 5
C) 3
D) 4
Correct Answer: C
Solution :
D must be perfect square |
\[\Rightarrow \] \[121-24a={{\lambda }^{2}}\] |
\[\Rightarrow \] Maximum value of \[\alpha \] is 5 |
\[\alpha =1\]\[\Rightarrow \] \[\lambda \notin I\] |
\[\alpha =2\]\[\Rightarrow \] \[\lambda \notin I\] \[\Rightarrow \]3 integral values |
\[\alpha =3\]\[\Rightarrow \] \[\lambda \notin I\] |
\[\alpha =4\]\[\Rightarrow \] \[\lambda \notin I\] |
\[\alpha =5\]\[\Rightarrow \] \[\lambda \notin I\] |
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