A) \[0<r<1\]
B) \[1<r<11\]
C) \[r>11\]
D) \[r=11\]
Correct Answer: B
Solution :
\[{{x}^{2}}+{{y}^{2}}-16x-20y+164={{r}^{2}}\] |
A (8, 10), \[{{R}_{1}}=r\] |
\[{{(x-4)}^{2}}+{{(y-7)}^{2}}=36\] |
B (4, 7), \[{{R}_{2}}=6\] |
\[\left| {{R}_{1}}-{{R}_{2}} \right|\,<\,AB\,<\,{{R}_{1}}+{{R}_{2}}\] |
\[\Rightarrow \] \[1<r<11.\] |
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