A) \[{{10}^{8}}\text{N/}{{\text{m}}^{2}}\]
B) \[{{10}^{4}}\text{N/}{{\text{m}}^{2}}\]
C) \[{{10}^{16}}\text{N/}{{\text{m}}^{2}}\]
D) \[{{10}^{3}}\text{N/}{{\text{m}}^{2}}\]
Correct Answer: D
Solution :
\[P=\frac{(2mV)N}{A}=\frac{2({{10}^{-26}})({{10}^{4}}){{10}^{22}}}{1}=2\frac{N}{{{m}^{2}}}\] NTA answer is [D] Carrer Point Option [Bonus.].You need to login to perform this action.
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