question_answer

For the circuit shown, with \[{{R}_{1}}=1.0\,\,\Omega ,\]\[{{R}_{2}}=2.0\,\Omega ,\]\[{{E}_{1}}=2V\] and \[{{E}_{2}}={{E}_{3}}=4V,\] the potential difference between the points 'a' and ?b? is approximately (in V):

A) 3.7

B) 2.7

C) 2.3

D) 3.3

Correct Answer: D

Solution :

\[\begin{matrix}    \begin{matrix}    \frac{2}{2}+\frac{4}{2}+\frac{4}{2}  \\    \frac{1}{2}+\frac{1}{2}+\frac{1}{2}  \\ \end{matrix}=\Delta V  \\ \end{matrix}\] \[\Delta V=\frac{5}{3/2}=3.3Volt.\]