A)
B)
C)
D)
Correct Answer: C
Solution :
\[-\frac{dT}{dt}=\frac{e\sigma A}{ms}4T_{0}^{3}(T-{{T}_{0}})\propto \frac{1}{pS}\] For \[A\,\rho s=800\times 2000=16\times {{10}^{5}}\] \[B\rho s={{10}^{3}}\times 4000=40\times {{10}^{5}}\] \[{{(\rho s)}_{B}}>{{(\rho s)}_{A}}\] \[\Rightarrow \] \[{{\left( -\frac{dT}{dt} \right)}_{B}}<{{\left( -\frac{dT}{dt} \right)}_{A}}.\]You need to login to perform this action.
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