A) 39
B) 31
C) 41
D) 49
Correct Answer: D
Solution :
Let \[x={{a}^{2}},y={{b}^{2}},z={{c}^{2}}\]. Then \[2{{b}^{2}}={{a}^{2}}+{{c}^{2}}\]since \[b\]is at least 2, consider the value of \[b\]from 2 onwards. The first such value occur when \[b\]=5(and then \[a=7,c=1\])so, the least possible value of \[x={{a}^{2}}=49\]You need to login to perform this action.
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