A) \[TiC{{l}_{2}}+2Mg\to Ti+2MgC{{l}_{2}}\] : Kroll
B) \[Ni\,{{(CO)}_{4}}\to Ni+4CO\] : Mond
C) \[A{{g}_{2}}C{{O}_{3}}\to 2Ag+C{{O}_{2}}+\frac{1}{2}{{O}_{2}}\] : Van Arkel
D) \[Zr{{I}_{4}}\to Zr+2{{I}_{2}}\] : Van Arkel
Correct Answer: C
Solution :
This process is simply calcinations.
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