A) \[2\times {{10}^{-\,8}}T\]along y-direction
B) \[6\times {{10}^{-\,8}}T\]along z-direction
C) \[2\times {{10}^{-\,8}}T\] along z-direction
D) \[6\times {{10}^{-\,8}}T\]along x-direction
Correct Answer: C
Solution :
\[B=\frac{E}{C}=\frac{6}{3\times {{10}^{8}}}=2\times {{10}^{-8}}(+z).\]You need to login to perform this action.
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